Blue Spheres Represent Nitrogen Atoms and Purple Spheres Represent Iodine AtomsFigure 1
If blue spheres represent nitrogen atoms, purple spheres represent iodine atoms, the reacting molecules are solid, and the products are gases, $(7.1,7.2)$ a. Write the formula for each of the reactants and products.b. write a balanced equation for the reaction.c. indicate the type of reaction as combination, decomposition, single replacement, double replacement, or combustion.
If blue spheres represent nitrogen atoms, purple spheres represent iodine atoms, the reacting molecules are solid, and the products are gases, $(7.1,7.2)$ a. Write the formula for each of the reactants and products. b. write a balanced equation for the reaction. c. indicate the type of reaction as combination, decomposition, single replacement, double replacement, or combustion.
Write a balanced chemical equation for each reaction.
a. Solid copper reacts with solid sulfur to form solid copper(I) sulfide.
b. Solid iron(III) oxide reacts with hydrogen gas to form solid iron and liquid water.
c. Sulfur dioxide gas reacts with oxygen gas to form sulfur trioxide gas.
d. Gaseous ammonia (NH3) reacts with gaseous oxygen to form gaseous nitrogen monoxide and gaseous water.
So this question it is asked, what is the equation that let's displace the reaction in the following image. Now the blue spears sarah and the rest of us uh not see the Blue spears existing. Uh die admitted that is this is a molecule that is a two molecules and threats. There are simply a molecular be. So we consider these are two and these are be the reds yourself be and these are two attempted is it combines to become A two. So there are 42 molecules, 1234 And simply there are also four molecules of being. So we can see that there are four molecules of two and there are four molecules of B. And in the right diagram it is uh on that each molecule has uh 100 days, one B and two atoms of. So we can see that this is A to be. Now there are 44 of this. So we can say there are four to be. And also we can see that the, uh, the question is already balanced, eight atoms okay, here eight times a day. And also there are four atoms of three and four times a week. So we can see that this is very question that best describes uh, yes, sir, in the image.
So chemistry is the study of matter and chemical reactions between substances. Where chemistry is also the study of matters. Composition, structure and properties. Yeah. So what we have is eight anos and 50 two's. And so with part A we see all eight eno's converted to an ITU's To have eight and 02s. Yeah. Yeah. What an equals eight. And in the next part we have 75% of B. Which is equal to eight, multiplied by 75, divided by 100. We get about six. So we have 6.02 molecules that will be formed. We have 302 molecules that are used So 02 remaining It's equal to and is equal to five. Take away three. We have to. Mhm. And so for the final part, if we have a 75% yield of six and 02 formed So the number of N 02 molecules present after the reaction we have And is equal to six. Mhm.
Problem 74 Chapter 18 and chemistry Central Science. So they want the right balance. Come in. Question for the following reactions. I've done so here. Yeah. Now we're goingto explain. So nitric oxide undergoes boat association in the upper atmosphere. So far, the association means that your molecules explosive light and it breaks up into individual elements. Now be natural. Dockside undergoes photo ionization the upper atmosphere. So nitric oxide will well reactive lights and it will lose one electron photo ionization. You'd be it lionizes do the present due to its interaction flight. Ah, see, nitric oxide undergoes oxidation by ozone any stratosphere. So Pedrick Darkseid will direct of ozone Bruce and a two and oxygen no nitric Dex connection. Backside sells awarded form nitric acid and nitric oxide. So Anna to plus water form centric acid plus eno
Until, for part A. The equation for the reaction is N g all too edgy. Mercury plus oxygen molecule. The same equation with the oxidation number off all participants. Margaret is here. We have n g all a G plus or two. Yeah, plus two minus two zero Digital. The half friction for this evictions are here oxidation her fiction and to reduction off reaction oxidation have reaction is toe all yeah, or two less for electrons in next ECI plus two less two electrons toe edge G mercury. Since there are twice as many electrons release in the oxidation, all fiction then I consumed in the reduction reaction. When adding these two reactions, we multiply the reduction reaction by two. Therefore, we have a reaction here to G or to H G plus or two solution for part B. The equation for the reaction is See you less a d in a tree, a g plus c a in a tree hall too. The same equation with the oxidation number off all perseverance. Margaret here is See you plus N g in all three N. G plus. See you. You know three hold to zero plus one plus five minus two zero plus two plus five minus two. The half reactions for this reaction or oxidation off reaction and reduction of reaction. See you to see you, plus two less two electrons and next a D positive plus electron edgy, since there are twice this many electrons releasing oxidation half election, then consumed in direction reaction when adding these two reactions, we want to apply the reduction reach in by two year far we have the equation became C U plus Too edgy, you know, three to do energy, plus See you and a three hole to. Now we check these Spectators signs to make sure that they are balanced properly, since in this case, they are they they are there is no need for any original steps.
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